A torque of 2.00 N.m is applied to a 10.0 kg object to give it an angular acceleration.If the angular acceleration is 1.75 rad/s²,then the moment of inertia is A) 1.95 kg m². B) 1.05 kg m². C) 1.14 kg m². D) 1.20 kg m². E) 1.35 kg m².

Question

Quizplus · Accepted Answer

The moment of inertia can be calculated using the formula: τ = Iα where τ is the torque, I is the moment of inertia, and α is the angular acceleration. Rearranging the formula gives: I = τ/α Substituting the values given in the problem, I = (2.00 NF1F1F1S1F1F1F10m) / (1.75 rad/s²) I = 1.14 kg m² Therefore, the correct answer is option C, 1.14 kg m².

A Torque of 2